quadrilaterals and coordinate geometry answers
ibly a rhombus. Find diagonals AC: \[ \sqrt{(7 - 1)^2 + (2 - 2)^2} = \sqrt{6^2 + 0} = 6 \] BD: \[ \sqrt{(4 - 4)^2 + (-2 - 6)^2} = \sqrt{0 + (-8)^2} = 8 \] Use the Shoelace Theorem for area Vertices ordered as \(A(1, 2)\), \(B(4, 6)\), \(C(7, 2)\)